String concatenation with string literal and non string literal [duplicate]

Question

I want to understand what the following declaration means:

constexpr auto type = u"bluetooth-opp-transfer-complete"_ns;

I know constexpr evaluates things at compile time, but what does u mean here? Also will _ns gets appended here? if yes then how cause _ns is not defined anywhere.

en.cppreference.com/w/cpp/language/string_literal

Marek R
– Marek R

2023-06-12 11:21:30 +00:00
Commented Jun 12, 2023 at 11:21 — Marek R
– Marek R, Commented Jun 12, 2023 at 11:21

Pzc · Accepted Answer · 2023-06-12 11:09:08Z

1

The u makes it a UTF-16 string literal. For more options see cppreference, for example.

answered Jun 12, 2023 at 11:09

Pzc

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