python: split string after a character

Question

I have a string with two "-"

467.2-123-hdxdlfow

I want to remove everything after the second "-" so that I get "467.2-123". What is the best way to do this?

ironMover · Accepted Answer · 2014-07-08 16:53:01Z

13

before, sep, after = theString.rpartition("-")

This splits the str about the last occurrence of "-" and your answer would be the variable before.

edited Jul 8, 2014 at 16:53

ironMover

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answered Oct 5, 2011 at 11:57

gibraltar

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Comments

Fredrik Pihl · Accepted Answer · 2011-10-05 11:57:55Z

10

In [6]: "-".join('467.2-123-hdxdlfow'.split('-')[0:2])
Out[6]: '467.2-123'

answered Oct 5, 2011 at 11:57

Fredrik Pihl

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Comments

Frank · Accepted Answer · 2011-10-05 11:55:54Z

2

 >>> s = '467.2-123-hdxdlfow'
 >>> s[:s.rfind('-')]
 '467.2-123'

answered Oct 5, 2011 at 11:55

Frank

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1 Comment

karnok Over a year ago

I like this one best because it works for any number of dashes - it will get rid of the last one and anything after it :)

fuhoi · Accepted Answer · 2011-10-05 12:16:00Z

2

If you are after everything but the last element, I have modifed spicavigo's answer to exclude the last element.

a='467.2-123-hdxdlfow'
'-'.join(a.split('-')[:-1])

answered Oct 5, 2011 at 12:16

fuhoi

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Comments

spicavigo · Accepted Answer · 2011-10-05 11:59:04Z

1

a='467.2-123-hdxdlfow'
'-'.join(a.split('-')[:2])

If you have exactly 2 '-', you could do

a.rsplit('-',1)[0]

answered Oct 5, 2011 at 11:59

spicavigo

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Comments

deamon · Accepted Answer · 2011-10-05 11:54:27Z

0

Try this regex

([^-]*-[^-]*)-.*

and ask the result for the first capturing group ((...) in the example).

answered Oct 5, 2011 at 11:54

deamon

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Comments

Narendra Yadala · Accepted Answer · 2011-10-05 12:03:09Z

0

You can try this result = re.sub("([^-]*-[^-]*)(-.*$)", r"\1", '467.2-123-hdxdlfow') gives 467.2-123

answered Oct 5, 2011 at 12:03

Narendra Yadala

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