String1 = “Python is an interpreted high level general purpose programming language”
List1 = String1.split()
for i in List1:
for j in i:
if i.count(j)>1:
List1.remove(i)
break
print(“ “.join(List1))
output:
Python is an high general programming
Expected output:
Python is an
Let me know the mistake I am making
try this code
String1 = "Python is an interpreted high level general purpose programming language"
List1 = String1.split()
ResultList = []
for i in List1:
has_repeated_letter = False
for j in i:
if i.count(j) > 1:
has_repeated_letter = True
break
if not has_repeated_letter:
ResultList.append(i)
print(" ".join(ResultList))
Using a regex approach:
inp = "Python is an interpreted high level general purpose programming language"
words = inp.split()
output = [x for x in words if not re.search(r'(\w)(?=.*\1)', x)]
print(output) # ['Python', 'is', 'an']
The regex pattern used here will match any word for which any character occurs two or more times:
(\w) match any single letter and capture in \1(?=.*\1) assert that this same character occurs later in the wordOne problem is removing from a list while iterating it. It is almost always more useful to rebuild the list with the elements you do want:
List1 = [i for i in List1 if len(i) == len(set(i))]
# ['Python', 'is', 'an']
Turning the strings into sets removes duplicate letters. Hence the length comparison with the original string. You retain only those with only unique letters.
