Handling asyncronous function in a loop [duplicate]

Question

I have the following code :

async def async_function():
    await some_function()


# TODO : Doesn't work
def sync_function():
    for i in range (100):
        async_function()

In the past I had no loop in sync_function, so I managed to call async_function using asyncio.run(). Now that I have a this for loop, I don't find the proper way to handle my asynchronous function.

The current code throws the following warning

RuntimeWarning: coroutine 'async_function' was never awaited

And part of the logic in it is not done during runtime.

What would be the good way to do this ?

You can move the loop to an async function and await the async_function (recommended) or you can call asyncio.run as before but in the loop (should work but isn't efficient). — Michael Butscher
– Michael Butscher, Commented Jan 5, 2024 at 15:54

anom907 zat · Accepted Answer · 2024-01-05 16:00:52Z

1

You can use asyncio tasks (https://docs.python.org/3/library/asyncio-task.html). This is a working example:

import asyncio


async def async_function(i):
    """ dummy code """
    print("Hi from", i) 
    await asyncio.sleep(1)


def sync_function():
    for i in range(100):
        loop = asyncio.get_event_loop() # get asyncio loop
        loop.create_task(async_function(i))  # schedule task

    asyncio.get_event_loop().run_until_complete(asyncio.gather())  # run the asyncio.gather function, who's role is to run all scheduled tasks.


sync_function()

answered Jan 5, 2024 at 16:00

anom907 zat

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