How do you pass an array though a function in Objective-C?

Question

I need some help. I am new to Objective-C and trying to learn how to program iPhone Applications in Xcode 3.0. I am trying to pass my array through a function and am confused. Thank you for your help. Here is my code:

#import <Foundation/Foundation.h>

void add(int x) {
    NSLog(@"%i + 2 = %i", x, x + 2);
}


int main (int argc, const char * argv[]) {

 NSNumber *arrayNumber = [[NSNumber alloc] initWithInt:5];
 NSNumber *arrayNumber2 = [[NSNumber alloc] initWithInt:9];

 NSMutableArray *arrayNumbers = [[NSMutableArray alloc] initWithCapacity:1];

 [arrayNumbers addObject:arrayNumber];
 [arrayNumbers addObject:arrayNumber2];



 NSLog(@"object at index 0 = %i", [[arrayNumbers objectAtIndex:0] intValue]);
 NSLog(@"object at index 1 = %i", [[arrayNumbers objectAtIndex:1] intValue]);



for(NSNumber *answer in arrayNumbers) {
    add();
}


return 0;
}

I am confused by what to put in the parentheses in the part with add():

for(NSNumber *answer in arrayNumbers) {
    add();
}

millimoose · Accepted Answer · 2011-10-20 00:46:55Z

1

You need to unbox the NSNumber using -intValue like this:

for(NSNumber *answer in arrayNumbers) {
    add([answer intValue]);
}

answered Oct 20, 2011 at 0:46

millimoose

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