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I have noticed this behavior:

import itertools as iter

truc = iter.count(0)
trac = ["a",'b','c','d','e']
for i in range(3):
    zap = [x for x,y in zip(truc,trac)]
    print(zap)

which outputs

[0, 1, 2, 3, 4]
[6, 7, 8, 9, 10]
[12, 13, 14, 15, 16]

I don't understand why the second list is not ```[5,6,7,8,9]```. And the same goes for the third list, why it does not start at 11 ?

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  • 1
    zip() advances the iterators in left to right order - it calls next(truc), and then (possibly) next(trac). But when truc yields 5, trac has reached its end, so the overall zip() process ends. So the 5 gets wasted, it has no place in zip's output, and there's no way to stuff it back into the iterator it came from. Commented May 16, 2024 at 1:45
  • @jasonharper : I see, thank you ! Can you make your comment as a response so that I can mark it as an answer ? Commented May 16, 2024 at 2:28
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