How to extract a substring from URL

Question

I need some help with RegEx. I have a URL:

../../temporary/12357704$002cXX$002c302036261/-1;jsessionid=13817F357AB3CD30E0836AA89903A003

or

../../temporary/12337704$002cXX$002c30222261/-1;jsessionid=13817F357AB3CD30E0836AA89903A003

I want always to extract the part between '../../temporary/' and '$002..' so it is 12357704 and 12337704.

poplitea · Accepted Answer · 2011-10-25 00:37:32Z

1

How about this:

result = url.gsub(/^\.\.\/\.\.\/temporary\/(.*?)\$002.*/, "\\1")

This extracts anything after '../../temporary/' and before '$002..'. (Accomplished by .*?, which is "non-greedy").

answered Oct 25, 2011 at 0:37

poplitea

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Comments

Roland Mai · Accepted Answer · 2011-10-25 00:38:50Z

0

Here's a quick solution:

str.scan(/^..\/..\/temporary\/(\d*)?\$002.*$/).flatten.first

where str is your url.

answered Oct 25, 2011 at 0:38

Roland Mai

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numbers1311407 · Accepted Answer · 2011-10-25 00:38:55Z

0

Something like this would work, but of course you'd need to be sure that the URL matches, or match will return null.

var result = your_url.match(/temporary\/([^$]*)/)[1];

answered Oct 25, 2011 at 0:38

numbers1311407

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