Hy!
I want to parse a String to a Integer. The String is like the format for series: SXXEXXX
The Code should increase the episode.
Like: S01E01 --> S01E02 Also: S01E100 --> S01E101
Code:
String s = episodes.get(episodes.size()-1);
Log.e("DBManager",s);
if (s.split("E").length <= 2) {
int i = Integer.getInteger(s.split("E")[1].split(" ")[0]); //NullPointerEx
return s.split("E")[0]+"E"+String.valueOf(i++);
}
Log:
10-26 15:56:34.635: E/DBManager(932): S00E01
Integer.getInteger() is not the correct method to use.
You should be using Integer.valueOf()
Integer.getInteger(String s) will return the integer system property with the key s.
The null pointer occurs because this method can't find the property with the key you supply and returns null. Java then tries to unbox this to an int and null pointers.
The null pointer exception is occuring precisely because you leave the leading 0 in the string. If you really need to leave it in there though, the following code works for me:
int i = Integer.parseInt(s.split("E")[1].split(" ")[0]);
If I understand correctly, you want to split the episode name into the parts, then get the episode number and increment it by one to get the next episode number. Don't call this split method so many times, call it once.
String episodeName = episodes.get(episodes.size()-1);
Log.e("DBManager", episodeName);
string[] splittedName = episodeName.split("E");
string returnName = "";
if (splittedName.length == 2) {
if (splittedName[1].split(" ").length > 1) {
// do something if there's a episode name too
} else {
// gets the episode number
int i = Integer.valueOf(splittedName[1]);
// returns next episode full name
if (i < 9) {
returnName = splittedName[0] + "E0" + String.valueOf(i + 1);
} else {
returnName = splittedName[0] + "E" + String.valueOf(i + 1);
}
}
}
return returnName;
0s will not be output: 00 as an integer is 0, +1 = 1, String.valueOf("1") == 1.
<= 2is incorrect. It must be>= 2to be useful.