Disable built-in Javascript validation on a line-by-line basis in VSCode

Question

Note there is a very similar question here but that is asking about ESLint, which is a completely different thing.

I would like to be able to disable the built-in Javascript validation for only one line. This kind of thing:

I do not want to disable it globally, and I am not using ESLint.

That works for type errors, but not e.g. syntax errors. If you change asdasd to == you still get Expression expected. even with // @ts-ignore. — Timmmm
– Timmmm, Commented Dec 10, 2024 at 9:55
Javascript per se doesn't do any such validation. It's some linter in your IDE. How exactly that can be disabled depends on the exact linter being used. — deceze
– deceze ♦, Commented Dec 10, 2024 at 9:59
It's the built-in Javascript validation in VSCode, per the title. — Timmmm
– Timmmm, Commented Dec 10, 2024 at 10:02
@jabaa: That documentation is a bit misleading. See this later sentence: "You can leverage some of TypeScript's advanced type checking and error reporting functionality in regular JavaScript files too." Typescript support is built in, and it can be used to check Javascript. — Timmmm
– Timmmm, Commented Dec 11, 2024 at 14:44

Hao Wu · Accepted Answer · 2024-12-10 10:09:44Z

-1

I'm not sure why do you want to do that. If you just want to put a marker or placeholder in a javascript file without VSCode freaking out, try using javascript compatible syntaxes.

For instance:

const a = 1;

// the following code does nothing
`
whaterver
`

console.log(a); // 1

Then you could replace or do anything to `whaterver` without breaking the code.

Or even better, put it in a comment block.

answered Dec 10, 2024 at 10:09

Hao Wu

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5 Comments

Timmmm Dec 10, 2024 at 10:13

It's templated data. It can't go in a comment or a string.

Hao Wu Dec 10, 2024 at 10:22

I don’t see why it can’t. When replacing the template, removing the delimiters all together. It’s much easier this way, or you would probably need some kind of extension to do that.

Timmmm Dec 10, 2024 at 12:36

Because the template language I am using is Jinja2-like. It has to be {{foo}} which is not valid Javascript. I'm not just doing my_template.replace_all("whatever", ...

Hao Wu Dec 11, 2024 at 2:01

Sounds like an XY problem, you should've mentioned that in your original question.

Timmmm Dec 11, 2024 at 14:43

It's not. You've given an XY answer; you think I should have been asking a different question. But you're wrong.

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