sort() function is not returning the sorted array [duplicate]

Question

I am trying to Sort the following Array but for some odd reason it doesn't seem to work

$sizearray = Array ( 
    [0] => 39 
    [1] => 40 
    [2] => 41 
    [3] => 42 
    [4] => 43 
    [5] => 44 
    [6] => 45 
    [7] => 39 
    [8] => 40 
    [9] => 41 
    [10] => 42 
    [11] => 43 
    [12] => 44 
    [13] => 45 
    [14] => 39 
    [15] => >40 
    [16] => 41 
    [17] => 42 
    [18] => 43 
    [19] => 44 
    [20] => 45 
);

$sizearray = array_values(sort(array_unique($sizearray)));

And the following warnings shows up:

>Warning: array_values() [function.array-values]: The argument should be an array in 
>/home/starlet/public_html/productlist.php on line 349

Note: If i remove sort() function, the array_values() function runs fine.

Adam Wagner · Accepted Answer · 2011-11-04 04:54:29Z

2

That's because sort is in-place and returns a boolean.

From the docs:

bool sort ( array &$array [, int $sort_flags = SORT_REGULAR ] )

You'll probably need to do something like this:

$sizearray = array_unique($sizearray);
sort($sizearray);
$sizearray = array_values($sizearray);

answered Nov 4, 2011 at 4:54

Adam Wagner

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Community · Accepted Answer · 2020-06-20 09:12:55Z

1

From the docs:

Return Values

Returns TRUE on success or FALSE on failure.

Note how it does not say "Returns the sorted array". This is because sort() sorts in-place.

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Nov 4, 2011 at 4:54

Ignacio Vazquez-Abrams

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Comments

Motilal Soni · Accepted Answer · 2014-07-14 06:55:22Z

1

<?php

$fruits = array(
    "Orange1", "orange2", "Orange3", "orange20"
);
sort($fruits, SORT_NATURAL | SORT_FLAG_CASE);
foreach ($fruits as $key => $val) {
    echo "fruits[" . $key . "] = " . $val . "\n";
}

?>

The above example will output:

fruits[0] = Orange1
fruits[1] = orange2
fruits[2] = Orange3
fruits[3] = orange20

answered Jul 14, 2014 at 6:55

Motilal Soni

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