sort a list of dictionary of dictionary in python

Question

I just want to sort by first_name this list in python

list = [ { "profile" :  { "first_name" : "a", "last_name" : "b" } } ,
         { "profile" :  { "first_name" : "c", "last_name" : "d" } } ,
         { "profile" :  { "first_name" : "e", "last_name" : "f" } } ]

best not to use list as a variable name

John La Rooy
– John La Rooy

2011-11-05 02:09:01 +00:00
Commented Nov 5, 2011 at 2:09 — John La Rooy
– John La Rooy, Commented Nov 5, 2011 at 2:09

senderle · Accepted Answer · 2011-11-05 00:57:27Z

9

This should do it:

>>> sorted(lst, key=lambda x: x['profile']['first_name'])

answered Nov 5, 2011 at 0:57

senderle

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Comments

Jonathan Livni · Accepted Answer · 2012-09-21 15:59:56Z

7

To sort the list itself, use:

lst.sort(key=lambda x: x['profile']['first_name'])

To keep lst unsorted and return a sorted list use:

sorted(lst, key=lambda x: x['profile']['first_name'])

edited Sep 21, 2012 at 15:59

answered Nov 5, 2011 at 5:48

Jonathan Livni

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1 Comment

Jonathan Livni Over a year ago

@AtulMakwana - You many have used .sort() syntax instead of sorted()

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