I have a matrix A like
1 2 3 4 5
6 7 8 9 0
and I want to expand it with a row of ones to get
1 1 1 1 1
1 2 3 4 5
6 7 8 9 0
I create the row of ones with
col_size = size(A, 2);
ones_row = ones(1, col_size);
How can I add my ones_row to the matrix?
Once you have A and ones_row you do:
[ones_row; A]
This returns the following.
1 1 1 1 1
1 2 3 4 5
6 7 8 9 0
I would probably do it as suggested in the previous answer, however in some cases (when the matrix sizes get very big), a more memory friendly solution would be to preallocate a matrix of the correct size and use indexing to put the existing values in the correct place:
A = [ 1 2 3 4 5; 6 7 8 9 0 ];
B = ones(size(A) + [1,0]); % Create an array of ones that is one row longer
B(2:end,:) = A; % Replace the elements of B with elements from A
The reason why I say this is more memory friendly is because when we create a row of ones we need to allocate memory for a vector, and then when we concatenate we need to allocate memory again for the result of the concatenation. When we use indexing, there's no need to allocate an intermediate vector. It isn't really important in this example, but can be quite significant for larger matrices or operations performed thousands of times.
There's also a useful function in the Image Processing Toolbox - padarray:
A = [ 1 2 3 4 5; 6 7 8 9 0 ];
B = padarray(A,[1 0],1,'pre');
I can give a solution that can worked for any matrix.
suppose your matrix is A, A is m*n
n = size(A,2)
out = [ones(1,n);A]
This solution works for any matrix.
n columns, you cannot concatenate it with a row/s having only one column. Please read the question again.
A = rand(5,6); n = size(A,2); out = [ones(n,1);A]; Error using vertcat. Dimensions of arrays being concatenated are not consistent.`
size(A, 2) and ones(1, ..); - this is why Sardar said your answer adds nothing new.