The following code:
c=0 while c < len(demolist):
print ’demolist[’,c,’]=’,demolist[c]
c=c+1
Creates this output:
demolist[ 0 ]= life
demolist[ 1 ]= 42
demolist[ 2 ]= the universe
demolist[ 3 ]= 6
demolist[ 4 ]= and
demolist[ 5 ]= 7
demolist[ 6 ]= everything
What's up with the demolist[',c,'] format that is being printed in the while loop? Why does this give a number in the brackets, whereas putting demolist[c] there just prints that exactly?
The print statement receives four arguments (separated by commas):
’demolist[’ # string
c # integer
’]=’ # string
demolist[c] # result of list access
A clearer way to write that line is:
print 'demolist[ {0} ]= {1}'.format(c, demolist[c])
See it working on line: ideone
Note: You may also want to consider using enumerate here instead of a while loop.
for n, elem in enumerate(demolist):
print 'demolist[ {0} ]= {1}'.format(n, elem)
See it working on line: ideone
print ’demolist[’,c,’]=’,demolist[c] prints the string "demolist[", the value of c, the string "]=", and the value of demolist[c], separated by spaces.
c is an integer. demolist[c] returns the value at index c from the list, demolist.
print ’demolist[’,c,’]=’ prints the series of objects, with an implicit conversion to a string (which is why you don't need to explicitly convert c (an integer) to a string).
A better way of writing this code is
for idx, item in enumerate(demolist):
print 'demolist[%d] = %s' % (idx, item)
