java code to build a path

Question

I was trying to make a code that will take input from a user and prints out the file path. I came across a interesting example. But I got stuck understanding a line.

//gets input from the user
BufferedReader input = new BufferedReader(newInputStreamReader(s.getInputStream()));
String request = input.readLine();
String path = new String(); 

int start = 0;
int end = 0;

for (int a = 0; a < request.length(); a++) {
    if (request.charAt(a) == ' ' && start != 0) {
        end = a;
        break;
    } 
    if (request.charAt(a) == ' ' && start == 0) {
        start = a;
    }
}

path = request.substring(start + 2, end);

Why is a 2 is added at the end?

Apparently they don't want any of the user input until two characters after the first whitespace if there's spaces in the input. — Brian Roach
– Brian Roach, Commented Nov 19, 2011 at 16:57

Lucas · Accepted Answer · 2011-11-19 16:58:36Z

1

The java File class does most anything you need. What are you actually trying to do? What is the input? What kind of output are you looking for?

Per your comment, if you have a file in the working path called index.html, then you could:

File file = new File( "./index.html" );
System.out.println( file.getAbsolutePath() );

There is another method of the file class called getCanonicalPath() which may also be useful.

edited Nov 19, 2011 at 16:58

answered Nov 19, 2011 at 16:48

Lucas

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3 Comments

user1052462 Over a year ago

what i'm trying to do lets say i client sends a get method for index.html file. i'm trying to view the absolute path of that file.

Lucas Over a year ago

@user1052462, you would probably get a better response if you explain what you are trying to do in the first place. Then you likely would not have gotten voted down...

user1052462 Over a year ago

@Lucas..thanks for your advice and help..I'll keep it in mind next time.

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