Parsing issues while parsing xml response android

Question

Xml response is like , but in one tag , the text is this:

<Description>
    &lt;center&gt;&lt;strong&gt;&lt;span&gt;Warehouse / Building Maintenance&lt;/span&gt;&lt;/strong&gt;&lt;/center&gt;&lt;br /&gt;
    &lt;br /&gt;
    &lt;strong&gt;&lt;span&gt;I&lt;/span&gt;&lt;/strong&gt;&lt;span&gt;mmediate openings available in the local Perris area for warehouse/building building maintenance positions. &lt;br /&gt;
    &lt;br /&gt;
    &lt;strong&gt;Job Description:&lt;/strong&gt;&lt;br /&gt;
    &lt;/span&gt;
    &lt;ul&gt;
        &lt;li&gt;&lt;span&gt;Associates will be responsible to define pieces of equipment that will paralyze operations if they fail, and plan whatever level of preventative maintenance necessary. &lt;br /&gt;
        &lt;/span&gt;&lt;/li&gt;
        &lt;li&gt;&lt;span&gt
......
similar text
......
</Description>

I can't able to parse it in proper way.

I tried using Jsoup.parse((nodeValue))

and Html.fromHtml(String) also URLEncoder.encode(String)

but its returning simple & symbol thats it.

How to parse this type of response?

Sephy · Accepted Answer · 2011-11-21 09:08:59Z

1

A temporary solution could be applying replaceAll("<", "<").replaceAll(">", ">") if API methods aren't working, but arent you supposed to use Html.toHtml(string) when you have stuff encoded and want it to become real html ?

answered Nov 21, 2011 at 9:08

Sephy

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1 Comment

Sephy Over a year ago

you mean the full string is replaced by & ?

Uday · Accepted Answer · 2011-11-21 09:53:01Z

0

Actually its returning only & symbol , that's because the nodelist item returns only single value.

After using like this:

NodeList fstNm = fstNmElmnt.getChildNodes();

                    System.out.println("nodefstnm"+fstNm.getLength());

                    for(int j=0;j<fstNm.getLength();j++) {
                       String val = ((Node) fstNm.item(j)).getNodeValue();
                       nodeValue=nodeValue.concat(val);
                    }

and then parsing with Jsoup., returns what I want.

answered Nov 21, 2011 at 9:53

Uday

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