When formatting a number into a string, I can limit the characters after a decimal point with, e.g., %.03f (display three digits after the point), but how do I also remove all digits BEFORE the point?
For example, I'd like 100.943 to format to ".943".
I think the only way for you to do that would be to remove the number before the decimal point using math, or string manipulation after the fact, like componentsSeparatedByString:@"."
A simple math way of removing it would be:
float initialValue = 100.943f;
int beforeDecimal = (int)initialValue;
float afterDecimal = initialValue - beforeDecimal;
Use an NSNumberFormatter, and set its maximumIntegerDigits to 0:
float f = 123.456;
NSNumber * nF = [NSNumber numberWithFloat:f];
NSNumberFormatter * formatter = [[NSNumberFormatter alloc] init];
[formatter setMaximumIntegerDigits:0];
NSLog(@"%@", [formatter stringFromNumber:nF]);
2011-11-23 18:36:59.138 NoIntegerDigits[21834:903] .456
stringWithFormat: is not designed to do intricate formatting tasks; it's just a quick way to get primitives into an NSString. The fact that specifiers such as %.03 work is probably due to it being built on sscanf. If you have specific formatting needs, use a formatter object.Ok I guess i got your question now..
Here is another solution where you will get strings out of string only.
example:
NSString *floatAsString = @"123.456";
NSArray stringDivisions = [floatAsString componentsSeparatedByString:@"."];
Here what you will get in array is: 123 and 456 to separate string objects. Once you get two separate strings, you can play with them.
This is what you needed ?
Simple way to do that, Here is an example,
Firstly convert your string to float value.
float x = 102.943;
int y = x;
float ans = x % y;
NSLog(@"\nx : %f \ny : %d \nans : %f", x, y, ans);
So the output will be:
x : 102.943000
y : 102
ans : 0.943000
Hope this is what you needed.
