What is the syntax to declare a C function that returns an Objective-C block? Is it possible?
I thought it should be something like
(void (^)(void)) myFunctionReturningABlock();
but that won't compile.
-
1When you say doesn't work, could you elaborate a little? Does it break at runtime or does it generate a compiler error or warning? Let us know what "doesn't work" means and we can help you further.Jasarien– Jasarien2011-11-28 14:05:06 +00:00Commented Nov 28, 2011 at 14:05
-
2possible duplicate of Objective-C Block type as return valueFerruccio– Ferruccio2011-11-28 14:08:27 +00:00Commented Nov 28, 2011 at 14:08
-
@Jasarien Sorry, I'm getting lazy. Fixed.Nick Moore– Nick Moore2011-11-29 15:08:24 +00:00Commented Nov 29, 2011 at 15:08
Add a comment
|
1 Answer
The syntax for your function is slightly incorrect.
As I understand it, you should define your block as a type which you can use as the return type for your function like this:
typedef void(^MyAwesomeBlock)(void);
MyAwesomeBlock blockFunction()
{
MyAwesomeBlock block = ^{
//some code;
};
return block;
}
4 Comments
Nick Moore
Thanks, that works perfectly. I also tried the 'typedef-less' version in the linked possible duplicate, but having a typedef makes it so much clearer.
nielsbot
Is there a typedef-less version of this?
Jasarien
@nielsbot if you read the comment just above yours, you'll notice that Nick refers to a typedef-less linked in a comment on the question, further up the page. But as Nick says, using a typedef makes the code much more readable - you generally don't want a typedef-less version, unless you want messy unreadable code?? :/
nielsbot
oh.. I looked for it here... I see it's in an answer to a question linked to via a comment on this question ;-)