PHP - REGEX get each part of a date into a seperate variable

Question

I have a string date like this:

$date = "23/12/2011";//format: dd/mm/yyyy.

I need each part of this date in its own variable, so that $d=="23", $m=="12", and $y=="2011".

Any suggestions on how to do this would be appreciated...

Regular expressions: enjoy responsibly.

Jon
– Jon

2011-12-05 18:16:04 +00:00
Commented Dec 5, 2011 at 18:16 — Jon
– Jon, Commented Dec 5, 2011 at 18:16

Sudhir Bastakoti · Accepted Answer · 2011-12-05 18:15:12Z

7

You could just do:

list($day, $month, $year) = split("[/]", $yourDate);

answered Dec 5, 2011 at 18:15

Sudhir Bastakoti

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5 Comments

user142162 Over a year ago

explode() should be used over split() in this case.

user895378 Over a year ago

@TimCooper Am I correct in understanding that to mean there is an appreciable performance difference between explode and split? Nevermind, the phpdocs answered that question for me.

user142162 Over a year ago

@rdlowrey: Between explode() and split(), not explode() and list.

ckruse Over a year ago

split() is deprecated since it uses the POSIX regex engine, you should avoid it in favour for preg_split() (RegEx splitting with limited Unicode support), mb_split() for regex splitting with unicode support or explode() for regex-less splitting.

Joey Green Over a year ago

What if you are parsing the following date string "20120924".

ckruse · Accepted Answer · 2011-12-05 18:15:45Z

2

$date = "23/12/2011";
list($d,$m,$y) = explode('/', $date, 3)

answered Dec 5, 2011 at 18:15

ckruse

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Comments

philwinkle · Accepted Answer · 2011-12-05 18:15:33Z

1

The regex you're looking for is /(\d+)\/(\d+)\/(\d+)/ and in the preg_match they would be contained in the $matches array you define in the preg_match call.

See here: http://php.net/manual/en/function.preg-match.php

answered Dec 5, 2011 at 18:15

philwinkle

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Comments

FailedDev · Accepted Answer · 2011-12-05 18:15:48Z

1

Backreferences:

if (preg_match('%(\d{2})/(\d{2})/(\d{4})%', $subject, $regs)) {
    $result = $regs[1]; #first two digits are here.. etc..
}

answered Dec 5, 2011 at 18:15

FailedDev

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Comments

user142162 · Accepted Answer · 2011-12-05 18:17:48Z

1

With this solution, each variable is automatically assigned the proper datatype:

sscanf($date, '%d/%d/%d', $d, $m, $y);

answered Dec 5, 2011 at 18:17

user142162

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