The OR Operator (|) in Javascript does the same as parseInt? [duplicate]

Question

Possible Duplicate:
Using bitwise OR 0 to floor a number

Performs a bitwise OR on two expressions,eg:

console.log(12.22|0) // output --->12

where does the decimal go? it's the same as parseInt function

parseInt(12.22)  // output --->12

how does it work?

I would guess that bitwise OR causes the double precision 12.22 to get automatically converted to an integer before applying the bitwise OR operation because you can't do a bitwise OR on a float. 12.22|1 == 13. Vote to close as a dup of stackoverflow.com/questions/7487977/…. — jfriend00
– jfriend00, Commented Dec 7, 2011 at 9:50
You can not simply close the question. You can accept the answer by clicking the green "ok" next to the best answer. To close an answer, the community has to vote for the close. — Erik
– Erik, Commented Dec 7, 2011 at 10:09

Peter · Accepted Answer · 2011-12-07 10:02:13Z

2

parseInt is useful in cases where one is parsing strings such as "12px".

For example:

pasrseInt("12px"); // returns 12

However, this doesn't make any sense with bit-wise OR:

"12px" | 0; // returns 0

Performing a bit-wise OR is more like applying Math.floor() to a number -- bitwise operations work on 32-bit integers in Javascript.

answered Dec 7, 2011 at 10:02

Peter

4,06726 silver badges33 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

user128511 Over a year ago

It's like but not the same as applying Math.floor. It's the closer to applying Math.trunc although much much faster because it's not a function that could be replaced. It's an operator that can't be replaced. It's still not the same as Math.trunc as it will return different values for NaN | 0 vs Math.trunc(NaN)

Collectives™ on Stack Overflow

The OR Operator (|) in Javascript does the same as parseInt? [duplicate]

1 Answer 1

1 Comment

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Linked

Related