Launch PHP script from cron?

Question

I know you need to put /usr/local/bin/php -f in cron before path to php file e.g.

/10 * * * * /usr/local/bin/php -f /home/public_html/scrip.php

but should i use -q or -f?

When i run /usr/local/bin/php --help it does not show any -q option yet many tutorials online say -q.

jason · Accepted Answer · 2011-12-12 19:25:12Z

2

The -q option just suppresses output from the PHP executable. This is useful when running a PHP script as a cron job. So really, you should use both.

See "man php" for more information.

answered Dec 12, 2011 at 19:25

jason

1,2551 gold badge9 silver badges26 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

animuson · Accepted Answer · 2011-12-12 19:27:06Z

2

The -q stands for quiet mode which will suppress all the HTTP headers from being sent along with it. Anything outputted by the script will be just that output.

PHP has full documentation on command line options on their website.

answered Dec 12, 2011 at 19:27

animuson♦

54.9k28 gold badges142 silver badges150 bronze badges

Comments

Alex Turpin · Accepted Answer · 2011-12-12 19:27:14Z

2

According to the docs, -q does the following

Quiet-mode. Suppress HTTP header output (CGI only).

You don't really need any options to run a PHP script from cron.

answered Dec 12, 2011 at 19:27

Alex Turpin

47.9k23 gold badges118 silver badges146 bronze badges

2 Comments

animuson Over a year ago

@JohnA: Yes, the CLI version of PHP already suppresses HTTP headers.

jason Over a year ago

@JohnA: Correct. There is no need to suppress output when used as Apache (or other web server) module.

Collectives™ on Stack Overflow

Launch PHP script from cron?

3 Answers 3

Comments

Comments

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

Comments

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related