I cannot get this to work. I only want to get the string between 2 others in bash. Like this:
FOUND=$(echo "If show <start>THIS WORK<end> then it work" | **the magic**)
echo $FOUND
It seems so simple...
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Do you have <start> and <end> in your string? Or thats for us as reference? If not then what is your actual string and desired output? A bit more information would certainly help!jaypal singh– jaypal singh2011-12-19 23:44:18 +00:00Commented Dec 19, 2011 at 23:44
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@JaypalSingh the <start> and <end> is a reference. Can be any text :) $FOUND have only to show "THIS WORK"Rodrigo– Rodrigo2012-01-18 19:48:24 +00:00Commented Jan 18, 2012 at 19:48
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3 Answers
sed -n 's/.*<start>\(.*\)<end>.*/\1/p'
Comments
This can be done in bash without any external commands such as awk and sed. When doing a regex match in bash, the results of the match are put into a special array called BASH_REMATCH. The second element of this array contains the match from the first capture group.
data="If show <start>THIS WORK<end> then it work"
regex="<start>(.*)<end>"
[[ $data =~ $regex ]] && found="${BASH_REMATCH[1]}"
echo $found
This can also be done using perl regex in grep (GNU specific):
found=$(grep -Po '(?<=<start>).*(?=<end>)' <<< "If show <start>THIS WORK<end> then it work")
echo "$found"
Comments
If you have < start > and < end > in your string then this will work. Set the FS to < and >.
[jaypal:~/Temp] FOUND=$(echo "If show <start>THIS WORK<end> then it work" |
awk -v FS="[<>]" '{print $3}')
[jaypal:~/Temp] echo $FOUND
THIS WORK
