I know how to do it with cout:
cout << "string" << 'c' << 33;
But how to perform this so output is redirected to variable instead directly to standard out ?
const char* string << "string" << 'c' << 33; //doesn't work
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2 Answers
Use std::stringstream from C++ standard library.
It works like the following:
std::stringstream ss;
ss << "string" << 'c' << 33;
std::string str = ss.str();
const char* str_ansi_c = str.c_str();
Keep in mind str still needs to be in the scope while you are using C-style str_ansi_c.
3 Comments
Pubby
stringstream isn't a part of the STL.
Omnifarious
@Pubby: No, it's part of the C++ standard library. A minor point of pedantry. But computers are nothing if not pedantic.
Victor Zamanian
Should it not be
const char* str_ansi_c = str.c_str();?#include <sstream>
#include <iostream>
main()
{
std::stringstream ss;
ss << "string" << 'c' << 33;
std::string str = ss.str();
std::cout << str;
}
