'str' object is not callable in Django url pattern

Question

In my urls.py file, I have

urlpatterns = patterns('',
                       (r'^$',home_page),
                       #(r'^'+main_cagetory_url_string+'$','home_page'),
                       (r'^(?:cam_sanh|buoi_da_xanh|cam_da_xanh)$','home_page'),
                       (r'^admin/', include(admin.site.urls)),)

I want to use that pattern to access cam_sanh, buoi_da_xanh, cam_da_xanh page. But I receive error:

'str' object is not callable

How can I fix this bug?

Necrolyte2 · Accepted Answer · 2013-01-30 21:17:16Z

4

Django will attempt to lookup the view using the string you provide, however, you need to specify the full view path, aka, 'my_project.view_name'

Alternatively, you can do as Filip suggested and give it the view name as the callback but then you need to import the view into your urls.py file.

answered Jan 30, 2013 at 21:17

Necrolyte2

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Filip Dupanović · Accepted Answer · 2011-12-25 10:03:44Z

2

For this line specifically, (r'^(?:cam_sanh|buoi_da_xanh|cam_da_xanh)$','home_page'),, the second tuple element should be a callback function, not a string.

This should fix it:

urlpatterns = patterns('',
    (r'^$',home_page),
    (r'^(?:cam_sanh|buoi_da_xanh|cam_da_xanh)$',home_page),
    (r'^admin/', include(admin.site.urls)),
)

answered Dec 25, 2011 at 10:03

Filip Dupanović

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