Django Models "IndexError: list index out of range" Pydev

Question

I have a Django project in Eclipse PyDev.

I have a file views.py which has the line:

from models import ingredient2

In models.py I have:

from django.db import models
class ingredient2(models.Model):
     ingredient     = models.CharField(max_length=200)

When I try to run the app I get the following error:

File "C:\Python27\lib\site-packages\django\db\models\base.py", line 54, in __new__
kwargs = {"app_label": model_module.__name__.split('.')[-2]}
IndexError: list index out of range

I did sync the database and started the server running.

I went into base.py and added 2 print statements (yes, I probably should not edit Django's files):

if getattr(meta, 'app_label', None) is None:
            # Figure out the app_label by looking one level up.
            # For 'django.contrib.sites.models', this would be 'sites'.
            model_module = sys.modules[new_class.__module__]
            print model_module #ADDED
            print model_module.__name__ #ADDED
            kwargs = {"app_label": model_module.__name__.split('.')[-2]}

They print out:

<module 'models' from 'C:\Users\Tine\workspace\slangen\slangen2\bolig\models.pyc'>

models

manage.py is contained within the bolig folder. I think the correct app label would be "bolig". The app worked several months ago and now, when I come back to it, something is not right. I have been creating other projects in PyDev.

This may be your same problem: stackoverflow.com/questions/4382032/… — AJJ
– AJJ, Commented Jan 7, 2012 at 10:15

Steve Robinson · Accepted Answer · 2013-02-01 19:57:36Z

8

Add a meta class with an app_label inside your model class definition:

class Foo:
    id = models.BigIntegerField(primary_key=True)
    class Meta:
        app_label = 'foo'

answered Feb 1, 2013 at 19:57

Steve Robinson

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Comments

wobbily_col · Accepted Answer · 2015-02-19 20:25:04Z

3

I had something similar

instead of

from models import ingredient2

try :

from your_app_name.models import ingredient2

answered Feb 19, 2015 at 20:25

wobbily_col

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user984003 · Accepted Answer · 2012-02-12 08:14:03Z

0

Well, not really an answer, but... I ended up creating a new django project and then copying in my code. That fixed the problem.

answered Feb 12, 2012 at 8:14

user984003

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Nelson Benítez León · Accepted Answer · 2012-10-06 13:02:14Z

0

I was also getting the kwargs = {"app_label": model_module.__name__.split('.')[-2]} error when using PyDev. In my case, the project wasn't refreshed before I tried to run it. As soon as I refreshed it, all was well again.

edited Oct 6, 2012 at 13:02

Nelson Benítez León

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answered Oct 3, 2012 at 12:32

Anonymous Joe

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Comments

Zaky German · Accepted Answer · 2013-04-10 17:34:47Z

0

I ran into this problem using Eclipse, Django and PyDev. I needed to have the application (instead of some .py file for example) selected in the PyDev Package Explorer (left panel) before clicking Run for everything to work properly.

answered Apr 10, 2013 at 17:34

Zaky German

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beginner · Accepted Answer · 2013-10-17 07:59:36Z

-1

in my case, models.py contains models

when I import models to other .py, say views.py it doesn't raise error when I run views.py

but when I run models.py, it raise the same error.

so I will just don't run in the models.py

answered Oct 17, 2013 at 7:59

beginner

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