double json response

Question

I don't know why this double json response are not successful:

[{"first_content":"content",...}][{"second_content":"content",...}]

So i am getting the message Oops! Try Again.

if(isset($_GET['start'])) {
    echo get_posts($db, $_GET['start'], $_GET['desiredPosts']);
    echo get_posts1($db, $_GET['start'], $_GET['desiredPosts']);
    $_SESSION['posts_start']+= $_GET['desiredPosts'];
    die();
}


var start = <?php echo $_SESSION['posts_start']; ?>;
var desiredPosts = <?php echo $number_of_posts; ?>;
var loadMore = $('#load-more');

loadMore.click(function () {
                loadMore.addClass('activate').text('Loading...');
                $.ajax({
                    url: 'profile.php',
                    data: {
                        'start': start,
                        'desiredPosts': desiredPosts
                    },
                    type: 'get',
                    dataType: 'json',
                    cache: false,
                    success: function (responseJSON, responseJSON1) {
                        alert(responseJSON);
                        loadMore.text('Load More');
                        start += desiredPosts;
                        postHandler(responseJSON, responseJSON1);
                    },
                    error: function () {
                        loadMore.text('Oops! Try Again.');
                    },
                    complete: function () {
                        loadMore.removeClass('activate');
                    }
                });
            });

What is the solution to get a double json response ? With one there is no problem

jValdron · Accepted Answer · 2012-01-11 19:40:09Z

6

"Double JSON response" as you call them is basically invalid JSON. You should have something like so:

{"first_content":"content", "second_content":"content",...}

Or as a couple of people mentioned:

[{"first_content":"content",...}, {"second_content":"content",...}]

You probably need to modify some server side code, your get_posts function could return a PHP array instead of a JSON array. Example:

function get_posts(){
    $array = array('content' => 'foo', 'title' => 'bar');
    return $array;
}

Then in your profile.php:

if(isset($_GET['start'])) {
    $posts = get_posts($db, $_GET['start'], $_GET['desiredPosts']);
    $posts1 = get_posts1($db, $_GET['start'], $_GET['desiredPosts']);
    echo array($posts, $posts1);
    $_SESSION['posts_start']+= $_GET['desiredPosts'];
    die();
}

edited Jan 11, 2012 at 19:40

answered Jan 11, 2012 at 19:13

jValdron

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7 Comments

Mark Schultheiss Over a year ago

or wrap the arrays in a object

Pawel Veselov Over a year ago

rather should be [{"first_content":"content",...},{"second_content":"content",...}]

Daniel Over a year ago

The json content are from two independently queries.

jValdron Over a year ago

Are you the one generating the JSON with a server side code? Could we see the code?

jValdron Over a year ago

Ohh I see what you're doing, you're using get_posts to output a JSON array. Personally, I'd make get_posts generate PHP arrays, then merge the 2 of them with array_merge and then use json_encode on the merged array.

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