How to take an object array value in php?

Question

Get object 's array value in php

 $obj = new Basecamp($bcUrl, $bcApikey, 'X', 'simplexml');

while print the object

    print_r($obj);

Get array as following:

Basecamp Object
(
    [request:protected] => 
    [baseurl:protected] => https://test.basecamphq.com/
    [format:protected] => simplexml
    [username:protected] => 5d4dsh8745hkf876kjdfhkfsd843ea46a
    [password:protected] => X
    [request_body:protected] => 
)

I want to take value of [baseurl:protected] i.e get 'https://test.basecamphq.com/' only from this object.

deceze · Accepted Answer · 2012-01-12 07:58:46Z

4

[baseurl:protected] means that the object has a property called baseurl which has a visibility of protected. That means you can specifically not access it directly from outside the class. Look in the documentation of the class how you're supposed to access it. It probably has a method like getBaseurl that allows you to do so.

answered Jan 12, 2012 at 7:58

deceze♦

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Linus Kleen · Accepted Answer · 2012-01-12 07:58:44Z

1

Assuming, its basecamp-php-api you're using, Basecamp class has a getBaseurl() method with which the base URL is retrievable.

If it's not, you could extend the Basecamp class like this in order to access protected members:

class MyBasecamp extends Basecamp {
   public function getBaseurl() {
      return $this->baseurl;
   }
}

answered Jan 12, 2012 at 7:58

Linus Kleen

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Comments

Timur · Accepted Answer · 2012-01-12 07:59:53Z

0

You cannot get value of baseurl property of BaseCamp object outside of it, because it is protected. You need to use some getter method.

answered Jan 12, 2012 at 7:59

Timur

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