How to replace every single characters, till the end of a line, using Java regex?
For Example: I want to replace every character with XXX right after = sign
contact.name=Stack Overflow
contact.name=XXX
3 Answers
Try this:
String example = "contact.name=Stack Overflow";
example = example.replaceAll("=.*", "=XXX");
4 Comments
mana
.replaceAll("=.*", "=XXX"); would be sufficient. The braces are redundant.
azeemigi
Ah this worked perfectly. Just what I looked for. Thank you for both of you, Oscar and Mana.
Óscar López
@azeemigi Please consider accepting the answer that was most helpful for you :) (mark the check to its left)
azeemigi
@Oscar I checked this answer :)
This should take care of it
Matcher matcher = Pattern.compile("=(.*?)\n").matcher(string);
if (matcher.find()) {
string = string.substring(0, string.length - matcher.group(1).length);
for (int i = 0; i < matcher.group(1).length; i ++) {
string += "X";
}
}
7 Comments
Dave Newton
Yikes, why not use
replaceAll?
Milad Naseri
Sorry, added too much complication. I thought we were after replacing each character with exactly one X.
Dave Newton
Hmm, I can understand why you thought that, the original question isn't quite clear.
Milad Naseri
No problem :) I'm glad you've found your answer
bojingo
I actually was looking for how to replace each character with exactly one X, and this was the top search result and helped me. I was hoping there was some way to do it with replaceAll, but I guess not.
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String ex = "contact.name=Stack Overflow";
ex = ex.replaceAll("=\w+(.*)", "=XXX");
