How to define a global instance of a php class?

Question

This is my code :

<?php
require_once 'classes/dbconnect.php';
$connector = new dbconnect();
pp();
function pp(){
$uid="0000007";
$table = $connector->query("SELECT * FROM tc_personal WHERE uid = '$uid'");
$tb = mysql_fetch_object($table);
print $tb->name;
}
?>

but this code will not work because the pp() function can't access the $connector. How can i define a global variable as $connector?

Mark Baker · Accepted Answer · 2012-01-24 07:35:26Z

9

Surely better than using globals, even if not OOP

<?php 
require_once 'classes/dbconnect.php'; 
$connector = new dbconnect(); 
pp($connector); 

function pp($connector){ 
    $uid="0000007"; 
    $table = $connector->query("SELECT * FROM tc_personal WHERE uid = '$uid'"); 
    $tb = mysql_fetch_object($table); 
    print $tb->name; 
} 
?>

answered Jan 24, 2012 at 7:35

Mark Baker

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3 Comments

AMIN Gholibeigian Over a year ago

Thanks , The global is easier.

Mark Baker Over a year ago

The global is also bad coding practise... easier !== better

Tarvo Mäesepp Over a year ago

Absolutely agreed with @MarkBaker, You should avoid globals as much as possible. This should be accepted one.

Dogbert · Accepted Answer · 2012-01-24 06:02:24Z

4

<?php
require_once 'classes/dbconnect.php';
global $connector;
$connector = new dbconnect();
pp();
function pp(){
global $connector;
$uid="0000007";
$table = $connector->query("SELECT * FROM tc_personal WHERE uid = '$uid'");
$tb = mysql_fetch_object($table);
print $tb->name;
}
?>

answered Jan 24, 2012 at 6:02

Dogbert

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