Regards to the following code:
int[] to = new int[] { text };
I understand it tries to define an array of integer, but What does the curly braces do in array definition?
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Yes, it looks like you are anonymously subclassing an array, but it is just an initializationPablo Grisafi– Pablo Grisafi2012-02-02 14:38:43 +00:00Commented Feb 2, 2012 at 14:38
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I mean if it's seen 5.5k times, it provides a decent quality content I suppose? I googled "curly braces java array" and got this. Better than scouring the ugly Java docs.Sticky– Sticky2016-09-12 22:15:52 +00:00Commented Sep 12, 2016 at 22:15
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5 Answers
This is just a shortcut code to create an array with initial elements, the followings (which are equal):
int[] to = new int[] { text };
int[] to = { text };
can be substituted with
int[] to = new int[1];
to[0] = text;
Hope this helps.
1 Comment
Chris Neve
After 4 years of Java development, I'm only discovering this syntax now. I don't understand why it's not used more. It's so much easier and more sexy than the way that's shown in all the docs - declaration, then manually setting each element in the array.
The curly braces contain values to populate the array.
This syntax allows you to define the contents of an array and is often referred to as an array literal.
In this context this can actually be simplified to:
int[] to = { 1, 2, 7, etc. };
Adding new int[] before it is only required when not part of an assignment, something like:
someFunction(new int[]{1, 3, 5});
Comments
Curly braces said to the compiler the values of the array
1 Comment
Leem.fin
So, currently there is only one element which is 'text', right?
Like SLaks said, curly braces is a way Java denotes a set. You can define the contents of the array using this method, but each element you define has to be the same type as the array.
