I'm trying to combine some text to a variable and output the value of the combined variable. For example:
testFILE=/tmp/some_file.log
function test_param {
echo $1
echo test$1
echo $(test$1) #this is where I want to output the value of the combined variable
}
test_param FILE
Output would be:
FILE
testFILE
/tmp/some_file.log <-- this is what I can't figure out.
Any ideas?
If I'm not using the correct terminology please correct me.
Thanks, Jared
Try the following:
#!/bin/bash
testFILE=/tmp/some_file.log
function test_param {
echo $1
echo test$1
varName=test$1
echo ${!varName}
}
test_param FILE
The ! before varName indicates that it should look up the variable based on the contents of $varName, so the output is:
FILE
testFILE
/tmp/some_file.log
do you mean this:
#!/bin/bash
testFILE=/tmp/some_file.log
function test_param {
echo $1
echo test$1
eval "echo \$test$1"
}
test_param FILE
output:
FILE
testFILE
/tmp/some_file.log
Try this:
testFILE=/tmp/some_file.log
function test_param {
echo $1
echo test$1
foo="test$1"
echo ${!foo}
}
${!foo} is an indirect parameter expansion. It says to take the value of foo and use it as the name of a parameter to expand. I think you need a simple variable name; I tried ${!test$1} without success.
Use ${!varname}
testFILE=/tmp/some_file.log
function test_param {
local tmpname="test$1"
echo "$1 - $tmpname"
echo "${!tmpname}"
}
test_param FILE
Output for that:
FILE - testFILE
/tmp/some_file.log
This worked for me. I both outputted the result, and stashed it as another variable.
#!/bin/bash
function concat
{
echo "Parameter: "$1
dummyVariable="some_variable"
echo "$1$dummyVariable"
newVariable="$1$dummyVariable"
echo "$newVariable"
}
concat "timmeragh "
exit 0
The output was:
Parameter: timmeragh
timmeragh some_variable
timmeragh some_variable
