Java - Splitting String based on multiple delimiters

Question

I essentially want to split up a string based on the sentences, therefore (for the sake of what I'm doing), whenever there is a !, ., ?, :, ;.

How would I achieve this with multiple items to split the array with?

Thanks!

Mat · Accepted Answer · 2012-02-05 14:17:28Z

28

String.split takes a regex to split on, so you can simply:

mystring.split("[!.?:;]");

answered Feb 5, 2012 at 14:17

Mat

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Louis Wasserman · Accepted Answer · 2012-02-05 18:50:13Z

8

Guava's Splitter is a bit more predictable than String.split().

Iterable<String> results = Splitter.on(CharMatcher.anyOf("!.?:;"))
   .trimResults() // only if you need it
   .omitEmptyStrings() // only if you need it
   .split(string);

and then you can use Iterables.toArray or Lists.newArrayList to wrap the output results how you like.

edited Feb 5, 2012 at 18:50

answered Feb 5, 2012 at 18:29

Louis Wasserman

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Jan · Accepted Answer · 2012-02-05 14:37:14Z

5

The argument of String.split is a regex, so you can create a pattern that matches any of those characters.

s.split("[.!:;?]");

edited Feb 5, 2012 at 14:37

answered Feb 5, 2012 at 14:23

Jan

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Smi · Accepted Answer · 2012-02-05 14:18:13Z

4

You can use the String.split(String regex) method with parameter "[!.?:;]".

answered Feb 5, 2012 at 14:18

Smi

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