How to check with regex validator minimum characters without count whitespace

Question

I mean like this

" T" It's no 3 Character
"T T" It's no 3 Character
" T " It isn.
"TTT" It's true
" TTT" is true
" TT T" is true

how to check that with regex

i'm trying "^[\s]{3,100}$" but it does'nt work

Thanks.

What do you want the answer to be for each one of the examples you gave? — escargot agile
– escargot agile, Commented Feb 6, 2012 at 8:47

Sam Greenhalgh · Accepted Answer · 2012-02-06 09:11:08Z

1

I'm assuming you want to test for at least three non-whitespace characters. In which case this pattern should work. ^\s*(\S\s*){3,100}$

    [Test]
    public void Test()
    {
        Regex pattern = new Regex(@"^\s*(\S\s*){3,100}$");

        Assert.IsFalse(pattern.IsMatch(" T"));
        Assert.IsFalse(pattern.IsMatch("T T"));
        Assert.IsFalse(pattern.IsMatch(" TT"));
        Assert.IsTrue(pattern.IsMatch("TTT"));
        Assert.IsTrue(pattern.IsMatch(" TTT"));
    }

What isn't clear from your question is if white space is allowed or if the match should fail if any white space is present.

edited Feb 6, 2012 at 9:11

answered Feb 6, 2012 at 8:51

Sam Greenhalgh

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2 Comments

Yusan Susandi Over a year ago

Thanks. but I'am try this " TTT" i'm type with 2 or more space in first it's not work, validator read not 3 characters entered. Thanks before

Sam Greenhalgh Over a year ago

I've updated the pattern to allow a proceeding \s* to work with your " TTT" scenario.

Eugene · Accepted Answer · 2012-02-06 08:52:29Z

0

I would say in Java because I am not familiar with asp.net (I am pretty sure you have lenght on String and replaceAll (regex, replacement) in asp.net as well):

System.out.println(input.length() == input.replaceAll("\\s", "").length());

answered Feb 6, 2012 at 8:52

Eugene

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Comments

Billy Moon · Accepted Answer · 2012-02-06 08:52:32Z

0

You can use regex /(\w)\1{2,}/ to match any character, followed by two or more of the same character like this in JavaScript: (you will have to translate to ASP.NET)

a = [" T ", "  T", "T  ", "TTT", "TTAT"]

for(i=0;i<a.length;i++)
  console.log(i, a[i], a[i].match(/(\w)\1{2,}/) != null)

answered Feb 6, 2012 at 8:52

Billy Moon

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1 Comment

Sam Greenhalgh Over a year ago

Does this address "minimum characters without count whitespace" ?

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