Split causes "Object doesn't support this property or method" exception

Question

call to split on a variable causes a "Object doesn't support this property or method" exception and I don't know why. Here's my code:

function getKontaktPersonen(kontaktSelectBox) {
   var kontaktPersonen = [];
   var id_and_name = kontaktSelectBox.attr('id');
   var id_part = getID_PartFromName(id_and_name);
   var textboxname;
   var selectboxname;
   if (kontaktSelectBox.attr('class') == 'kontaktSelectBox') {

        textboxname = "TextBoxKunde" + id_part;
        selectboxname = "SelectBoxKontaktPerson" + id_part;
    } else if (kontaktSelectBox.attr('class') == 'NewkontaktSelectBox') {
        textboxname = "NewTextBoxKunde" + id_part;
        selectboxname = "NewSelectBoxKontaktPerson" + id_part;
    } else {
        return false;
    }
    var kundeBox = $('#' + textboxname);
    var kundeBoxVal = kundeBox.val();
    if (kundeBoxVal != '' && kundeBoxVal != null) {
     var adr_id = kundeBoxVal.split(';')[1];
      //here comes an ajax call
      //[...]
    }
}

make sure that it is not null

Diode
– Diode

2012-02-09 08:21:52 +00:00
Commented Feb 9, 2012 at 8:21 — Diode
– Diode, Commented Feb 9, 2012 at 8:21
@Luke. What version? Try the code in Chrome or FF.

gdoron
– gdoron

2012-02-09 09:16:11 +00:00
Commented Feb 9, 2012 at 9:16 — gdoron
– gdoron, Commented Feb 9, 2012 at 9:16

Andrzej Doyle · Accepted Answer · 2012-02-09 08:41:39Z

2

If the selector didn't find any element the val function will return undefined Try this:

if (kundeBoxVal) {
     var adr_id = kundeBoxVal.split(';')[1];
 }

edited Feb 9, 2012 at 8:41

Andrzej Doyle

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answered Feb 9, 2012 at 8:23

gdoron

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2 Comments

James Allardice Over a year ago

He is checking kundeBoxVal != null and since null == undefined that should cover this case.

Luke Over a year ago

ok. the value was undefined. Now I need to find out why. But that's another story.

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