Basic pointer to array of class for c++

Question

AIBase* allai[2];
AIBase *z0AI = new AIA;
    AIBase *z1AI = new AIB;
allai[0] = z0AI;//this this gives me an error
allai[1]= z1AI;

AIBase is the superclass and AIA and AIB inherits from the AIBase what is wrong with the syntax ,i need some help in figuring this out error 1:

error C4430: missing type specifier - int assumed. Note: C++ does not support default-int error C2466: cannot allocate an array of constant size 0 error C2040: 'allai' : 'int []' differs in levels of indirection from 'AIBase *[2]'

Why must this code be in function scope? Cant this work in global scope?

Please don't make us guess. Show the error message (it's important). — Greg Hewgill
– Greg Hewgill, Commented Feb 11, 2012 at 7:58

Greg Hewgill · Accepted Answer · 2012-02-11 08:19:10Z

4

In C++ (and C), executable code that is not a variable initialiser must appear inside a function. Executable code cannot appear at file scope (that is, outside any function).

So, just put your code inside a function:

int main(int, char *[])
{
    AIBase* allai[2];
    AIBase *z0AI = new AIA;
    AIBase *z1AI = new AIB;
    allai[0] = z0AI;
    allai[1]= z1AI;
}

answered Feb 11, 2012 at 8:19

Greg Hewgill

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1 Comment

Mr Lister Over a year ago

This is correct. However, to be pedantic, it's only the last two lines that need to be inside a function; the first three can appear at file scope. (Not that it's recommended...)

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