Passing model to layout in MS MVC

Question

In views i`m passing model strongly typed way like this:

System.Web.Mvc.ViewPage<HomeModel>

And then just use it:

<%= Model.Greeting %>

How it would be possible to use strongly typed model in layout?

Without strongly typing i would probably add necessary data at controller factory, then use it through (LayoutModel)Viewdata["LayoutModel"]).Tralala, but i`m looking for better way.

eu-ge-ne · Accepted Answer · 2009-05-29 08:19:39Z

1

Create strongly typed property in your View:

<script runat="server">
    protected LayoutModel LayoutModel
    {
        get
        {
            return ViewData["LayoutModel"] as LayoutModel;
        }
    }
</script>

answered May 29, 2009 at 8:19

eu-ge-ne

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2 Comments

Arnis Lapsa Over a year ago

It's a bit better, but still not what i`m looking for.

Arnis Lapsa Over a year ago

Haven't found anything better so far. :/

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