PHP preg_match, how to capture only named regexs?

Question

So this is the problem, Im using preg_match, to match current URI from browser, with the ones defined in my router.php config file. Im building Router/Dispatcher similar to Django.

What I want is that preg_match() captures only named regexs in $matches variable.

So If I have regexs like this:

^(?<param1>[a-z]+(?:\-[a-z]+)*)\.domain\.com\/[a-z]+(?:\/)?(?<param2>[a-z]+)?\/?$

Rubural link: CLICK

When I compare current URI with this regexs it matches, but $matches variable returns this:

array ( 0 => 'sub.domain.com/page/pageurl/', 'param1' => 'sub', 1 => 'sub', 'param2' => 'pageurl', 2 => 'pageurl', )

Is it possible to tell preg_match() to return only named matches, and exclude those numeric one, what I would like to get is Associative Array :)

I could use foreach() and loop through $match and then inside check if its numeric or not... is there any better way?

Thanks

There isn't an array_filter_keys function, so you'll probably be best just doing the loop. — lonesomeday
– lonesomeday, Commented Feb 19, 2012 at 21:52
array_filter_keys can be done like: array_intersect_key($matches, array_flip(array('param1', 'param2'))) — Koen.
– Koen., Commented Jun 29, 2012 at 14:51

Niet the Dark Absol · Accepted Answer · 2012-02-19 21:57:14Z

4

I can't find anything in the PHP manuals about named subpatterns in the first place, but I'm going to take an educated guess and say that you can't prevent the numeric keys in the resulting array.

The ground for this guess is that key 0 always contains the full match, and there's no way of naming that match.

If you want to strip out numeric indices, the best way would probably be a foreach loop.

answered Feb 19, 2012 at 21:57

Niet the Dark Absol

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2 Comments

Vyktor Over a year ago

php.net/manual/en/regexp.reference.subpatterns.php >

It is possible to name a subpattern using the syntax (?P<name>pattern). This subpattern will then be indexed in the matches array by its normal numeric position and also by name. PHP 5.2.2 introduced two alternative syntaxes (?<name>pattern) and (?'name'pattern).

Limeni Over a year ago

Thanks guys, il leave both indexed and associative values. Who knows who will be using this Dispatcher so its better to leave both options.

Brian Webster · Accepted Answer · 2012-10-05 12:53:02Z

1

Try this code:

$namedFields = array_filter(array_keys($matches), "is_string");

edited Oct 5, 2012 at 12:53

Brian Webster

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answered Aug 23, 2012 at 19:40

Ricardo Carlini

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1 Comment

Cedric Over a year ago

The above didn't work for me. Instead, try : array_filter($matches, "is_string",ARRAY_FILTER_USE_KEY);

sectus · Accepted Answer · 2015-09-16 07:02:53Z

0

    $row = array_intersect_key(
        $matches,                     // 4. "filling" flipped key array with actual values
        array_flip(                   // 3. fliping array
            array_filter(             // 2. keeping string keys
                array_keys($matches), // 1. taking keys
                "is_string")));

also with php5.6 you could use array_filter

$row = array_filter(
    $matches,
    'is_string',
    ARRAY_FILTER_USE_KEY
);

edited Sep 16, 2015 at 7:02

answered Sep 16, 2015 at 5:51

sectus

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