PHP not reporting specific error (double opening php tag)

Question

I've just had a hard time finding a bug in my PHP code described below

<?php
if(condition...)
    {
     do something...
    }
<?php
...more php

Notice that I incorrectly opened a php block again when it was not needed(before the ...more php)

The problem is that PHP is not reporting this error, it's just giving me a blank page. I've set error reporting to E_ALL and ini_set display errors '1'. I was wondering if there is a way to make php report this kind of error.

Your Common Sense · Accepted Answer · 2012-02-29 11:32:50Z

1

This is very common problem, yet a quite simple one.

That's just error reporting settings.
Your server apparently set up to not to display errors (which is the only right behavior on a live server!), but most likely it writing errors in some log file.
You have to find out where this file located and peek for errors.

If it's not a live server, you may turn on display_errors setting in the php.ini

answered Feb 29, 2012 at 11:32

Your Common Sense

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1 Comment

user559533 Over a year ago

I checked my windows/temp/php-errors.log file and this error is not being logged, just some php notices. And I have error reporting set to E_ALL and display errors = 1 in the php file itself(actually an included config file)

kingmaple · Accepted Answer · 2012-02-29 11:32:02Z

0

What do you mean? PHP does detect that problem and does report the error, if you have errors turned on:

Parse error: syntax error, unexpected '<' in ### on line #

answered Feb 29, 2012 at 11:32

kingmaple

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