Regex to replace string with word and characters

Question

I've got three working regexp's,

string.replace(\catalogue\g, "") // replace a the word catalogue

string.replace(/[/:]/g, "") // replace the characters /, :

string.replace(\20%\g, "") // replace '20%'

Instead of replacing the string three times, I want to combine my regexp's.

Wanted result = 'removethewordnow';

var string = 'rem:ove20%the/word:catalogue20%now';

My latest try was:

string.replace(/\catalogue\b|[/20%:]/g, ""); // works, but catalouge is unaffected and 20% isn't combined as a word

I could be wrong, but I feel you're missing an "or" (|) statement — SpYk3HH
– SpYk3HH, Commented Mar 5, 2012 at 14:37
I wasn't escaping the c on purpose, just the whole word "catalogue" - but the first one actually works just fine. — patad
– patad, Commented Mar 5, 2012 at 14:50

Kristoffer Sall-Storgaard · Accepted Answer · 2012-03-05 14:39:15Z

2

Off the top of my head:

string.replace(/(catalogue|[\/:]|20%)/g,"");

answered Mar 5, 2012 at 14:39

Kristoffer Sall-Storgaard

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1 Comment

Petr Vostrel Over a year ago

Characters inside [] don't need backslashing, don't they?

Joey · Accepted Answer · 2012-03-05 14:39:00Z

2

Just use an alternative, i.e. separate each of the regular expressions you had before by the alternation operator |:

catalogue|20%|[/:]

Also note that you cannot just combine character classes and literal strings in the way you have done there. Above naïve combination works and everything beyond that might be optimisation (even if it can't be optimised further in this case) – but that only works if you don't change the language described by the regex.

answered Mar 5, 2012 at 14:39

Joey

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Comments

Tim Pietzcker · Accepted Answer · 2012-03-05 14:44:30Z

2

You seem to be having a typo there (\c), also you don't want 20% inside the character class (and you should escape the slash). You also need to remove the word boundaries if you want to allow catalogue20% to match - there is no boundary between catalogue and 20, therefore the \b fails:

string.replace(/catalogue|20%|[\/:]/g, "");

edited Mar 5, 2012 at 14:44

answered Mar 5, 2012 at 14:39

Tim Pietzcker

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Fabrizio Calderan · Accepted Answer · 2012-03-05 14:39:06Z

1

var string = 'rem:ove20%the/word:catalogue20%now';

string.replace(/([:/]|20%|catalogue)/g, '');

answered Mar 5, 2012 at 14:39

Fabrizio Calderan

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Roland Mai · Accepted Answer · 2012-03-05 14:40:30Z

0

\b refers to a word boundary, but your word catalogue is mixed with other words. So your regex should be:

string.replace(/catalogue|[\/20%:]/g, "");

Also do escape the / with \/.

answered Mar 5, 2012 at 14:40

Roland Mai

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1 Comment

patad Over a year ago

I read that you don't need to escape / if it's in the beginning or end of the characters, which it was in this case [/:20%]

xdazz · Accepted Answer · 2012-03-05 15:20:01Z

0

string.replace(/catalogue|20%|[/:]/g, '')

edited Mar 5, 2012 at 15:20

answered Mar 5, 2012 at 14:40

xdazz

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1 Comment

patad Over a year ago

why would you prefer to encapsule the words in brackets? both (catalogue)|(20%) and catalogue|20% seem to work..

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