jQuery/Javascript find and replace all instances [duplicate]

Question

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Replace all instances of a pattern with regular expressions in Javascript / jQuery
How can I use jQuery to style /parts/ of all instances of a specific word?

Say I have the code:

<div class="replace">
     <i>Blah</i>
     <u>Blah</u>
</div>

Now, I want to replace all the < within the div with something else.

If I use $('#div').html().replace('<','somethingElse'); it only replaces the first instance.

How can I replace all the instances?

Thanks

you need to use a little regex, Kevin B is refering to it I think correctly, /g is ur regex command to repeat after first find — SpYk3HH
– SpYk3HH, Commented Mar 14, 2012 at 19:20

ShankarSangoli · Accepted Answer · 2012-03-14 19:19:59Z

9

Use regex

"anyString".replace(/</g,'somethingElse');

If you want to replace it inside the div then try this.

$('#div').html($('#div').html().replace(/</g,'somethingElse'));

answered Mar 14, 2012 at 19:19

ShankarSangoli

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2 Comments

Phiber Over a year ago

How I do if I want to do this for whole html? $('#html').html($('#html').replace(/name/g, 'somethingElse')); does'nt work.

Mr_Spock Over a year ago

@Phiber Did you ever learn how? If so, let me know, please.

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