Passing variable arguments in PHP to one array without array declaration

Question

In PHP is there a way to pass variable arguments as a single array without requiring an array declaration?

I'm calling a function below like:

$this->layouts->add_include(array('css/style.css','css/internal.css'));

Is there any way in the function to make it accept multiple variable arguments without needing to declare the array like:

$this->layouts->add_include('css/style.css','css/internal.css');

If I do this above then I get the following error in my functions foreach loop using the second code sample:

 Invalid argument supplied for foreach()

For reference the function is:

public function add_include($array)     
{
$asset_path = 'assets/';
  foreach($array as $array_item) {

    $this->CI->load->helper('url'); // Just in case!
    $this->includes[] = base_url() . $asset_path . $array_item;
}

Scuzzy · Accepted Answer · 2012-03-15 02:43:01Z

1

func_get_args() can be used here

public function add_include()     
{
  $asset_path = 'assets/';
  foreach(func_get_args() as $array_item) {

    $this->CI->load->helper('url'); // Just in case!
    $this->includes[] = base_url() . $asset_path . $array_item;
}

answered Mar 15, 2012 at 2:43

Scuzzy

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1 Comment

jsuissa Over a year ago

Brilliant -- I knew about it, but didn't realize it'd work in this context. Thanks so much.

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