How to make this format of array in PHP?

Question

I want to make an array in PHP but it should be in specific format such this:

array(1, 5, 3)

I mean, I have the values 1, 5 and 3 from my database, so I had to loop it with the use of array_push

$a=array();

foreach( $db_nums as $db_num ){
array_push($a, $db_num);
}

print_r($a);

but it outputs:

Array ( [0] => 1 [1] => 5 [2] => 3 );

i want it to be only:

array(1, 5, 3 );

Any ideas how? Thanks a lot for any help!

I don't really understand your question? How do you mean in a specific format. — Cyclonecode
– Cyclonecode, Commented Mar 21, 2012 at 5:55
You're maybe looking for var_export? (php.net/var_export) Otherwise, no idea. — Corbin
– Corbin, Commented Mar 21, 2012 at 5:57
did you mean that the elements should be in ascending order? — prukuhkoo
– prukuhkoo, Commented Mar 21, 2012 at 5:57
all you need is $myarray = array(1,2,3) and you done with php — Khurram Ijaz
– Khurram Ijaz, Commented Mar 21, 2012 at 5:57
its not an array if there are no keys. array(1, 5, 3 ); is the same as Array ( [0] => 1 [1] => 5 [2] => 3 ); if you don't specify the keys php does it for you starting at 0 — user557846
– user557846, Commented Mar 21, 2012 at 6:12

Mr Wednesday · Accepted Answer · 2012-03-21 06:03:02Z

2

Just use the below code:

$Array = array(1,2,3);

Edit:

$a = array();

foreach( $db_nums as $db_num )
{
    $a[] = $db_num;
}

print_r($a);

answered Mar 21, 2012 at 5:57

Mr Wednesday

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Comments

Corbin · Accepted Answer · 2012-03-21 06:16:02Z

0

$db_nums = array(1, 2, 3); //pointless example, but comes from DB
$a = array();
foreach ($db_nums as $n) {
    $a[] = $n;
}
var_export($a);

That will output:

array (
  0 => 1,
  1 => 2,
  2 => 3,
)

Which is about as close as you're going to get without writing your own function to do it.

(Also note that in this example, you could just directly do var_export($db_nums).)

answered Mar 21, 2012 at 6:16

Corbin

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TryTryAgain · Accepted Answer · 2012-04-19 16:35:15Z

0

<?php  $array = array("foo", "bar", "hallo", "world");  var_dump($array); ?>

You can use that

TryTryAgain

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answered Mar 21, 2012 at 6:00

Mrugen Ramani

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