Creating new object with dynamic variables in PHP

Question

I want to create a new object using this

$procedure = new ${$s.'\\'.$p};

It doesn't work. Why isn't this possible?

@Michael No, '\' is invalid syntax, as for "\\" it doesn't make a difference. — x74x61
– x74x61, Commented Mar 25, 2012 at 20:37
@Michael, "\" is also the escape character. If you do single slash it will escape ' or " of the string and will cause a parse error. — sh03
– sh03, Commented Mar 25, 2012 at 20:38
@Michael , in that case it would be an extremely bad practice ... i try to assume unintentional stupid mistake , before intentional harmful code convention — tereško
– tereško, Commented Mar 25, 2012 at 20:43

sh03 · Accepted Answer · 2012-03-25 20:58:43Z

2

Why don't you

$name = "$s\\$p";
$procedure = new $name;

?

Also ${$s.'\\'.$p} means a variable, with a variable name that is clearly not good. If you are, and I think you are, trying to get something like an instance of Namespace\Class you should try with the code below.

I think that the {} shortcut only works with this syntax ${} which is clearly referring to a variable. So you cannot use it for instantiating new objects.

edited Mar 25, 2012 at 20:58

answered Mar 25, 2012 at 20:32

sh03

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3 Comments

x74x61 Over a year ago

I just want to understand. Besides, the first one is more compact.

sh03 Over a year ago

@x74x61, It have a strange behavior probably because of some problem in the namespace. I tried also with new {$s.'\\'.$p} but didn't work. If you have to use this thing so many times that you need a shortcut, maybe there's something wrong in your application.

Cristian Rodriguez Over a year ago

Yeah. however This is still is self-modifing code which is an awful idea to begin with.

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