User input stored in an array of char's (C++)

Question

I'm trying to back-up in my programming and learn something that I somehow missed (unless I'm not understanding the problem). I am trying to prompt the user to enter the name of a project, and I want to store that name in a variable. Normally I would use getline() or std::cin >> std::string some_string but the assignment is asking me to do this, without the use of strings. "You can NOT use the string class - instead use array's of characters." Therein lies the question: How do I take the user input and store them in an array of chars?

The user is going to enter a word and then hit enter... How do i capture that into an array of chars? If the word was coming in one char at a time I could just add it to the array, dynamically expanding if needed, but when it comes in a block of char's like that I am lost for ideas. Thanks!

Chad · Accepted Answer · 2012-04-02 20:57:32Z

5

The member function cin.getline() allows you to specify a character buffer and length.

char name[32];
cin.getline(name, 32);

Though any C++ assignment that would ask you specifically to use character arrays instead of strings (especially in this context), is suspect.

answered Apr 2, 2012 at 20:57

Chad

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5 Comments

karlphillip Over a year ago

cin.getline(name, sizeof(name));

Ben Voigt Over a year ago

@karl: Dangerous, because if name is changed to a pointer, it still compiles but does the wrong thing.

karlphillip Over a year ago

Of course, but this suggestion goes hand in hand with what is stated in the answer. If @Chad had used pointers, I would not have left my previous comment. :)

Chad Over a year ago

And that is why I say if an assignment is forcing you to use character arrays for this it is suspect. My guess is an old-fashioned "C with classes!" approach.

Ben Voigt Over a year ago

@karl: But it's fairly straightforward to use one of the countof implementations instead, which is completely safe. If you're going to replace the hard-coded constant with a computation, you might as well use the right computation.

Anthony · Accepted Answer · 2012-07-26 03:26:29Z

0

Try this:

char arr[100];
cin >> arr;

edited Jul 26, 2012 at 3:26

Anthony

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answered Apr 2, 2012 at 20:58

Ash Burlaczenko

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7 Comments

Amardeep AC9MF Over a year ago

Terrible idea. No way to guarantee the buffer won't overflow. This kind of thing leads to bugs down the road.

Robᵩ Over a year ago

Note: You must never do this after you finish this programming course. You have created a buffer overflow, which is the root cause of various security bugs.

Jesse Good Over a year ago

Call cin.width(100); beforehand.

Ben Voigt Over a year ago

@Amardeep: No way to guarantee it? Sure you can, just define template <size_t N> istream& operator>>(istream&, char (&)[N]) and check the length N therein.

Amardeep AC9MF Over a year ago

@Ben Voigt: That's plenty clever but does adding obscurity make a poor solution better than an intrinsically safer solution like Chad's?

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