ES6 how to avoid nested functions

Question

I have functions nested here in setTimeout

function startWorker (obj) {
  if (!code) {
    return setTimeout(2000, () => {
      startWorker(obj)
    });
  }

  console.log('worker started')
}

How do I correctly use startWorker as the callback without using more functions than needed.

What I'm trying to do:

I'm trying to run the same function with the same argument as the callback to a setTimeout inside without duplicating function calls.

@SᴀᴍOnᴇᴌᴀ I don't understand, this is actual code. — Harry
– Harry, Commented Apr 2, 2020 at 18:42
Okay I have retracted my close vote but bear in mind this tip from The Help center page How do I ask a good question?: "You will get more insightful reviews if you not only provide your code, but also give an explanation of what it does. The more detail, the better." — Sᴀᴍ Onᴇᴌᴀ
– Sᴀᴍ Onᴇᴌᴀ ♦, Commented Apr 2, 2020 at 18:45

thingEvery · Accepted Answer · 2020-04-02 22:26:49Z

2

I'm not sure I understand what you're asking, but what if you just use setInterval() instead of setTimeout()?

function startWorker(obj) {
  if (!code) {
    setInterval( () => {
      console.log(obj.action);
    }, 2000);
  }
}

const code = false;
const someObj = {
  action: "tick"
};

startWorker(someObj);

answered Apr 2, 2020 at 22:26

thingEvery

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