JS - Split string into substrings by regex

Question

Let's say I have a string that starts by 7878 and ends by 0d0a or 0D0A such as:

var string = "78780d0101234567890123450016efe20d0a";
var string2 = "78780d0101234567890123450016efe20d0a78780d0103588990504943870016efe20d0a";
var string 3 = "78780d0101234567890123450016efe20d0a78780d0103588990504943870016efe20d0a78780d0101234567890123450016efe20d0a"

How can I split it by regex so it becomes an array like:

['78780d0101234567890123450016efe20d0a']
['78780d0101234567890123450016efe20d0a','78780d0101234567890123450016efe20d0a']
['78780d0101234567890123450016efe20d0a','78780d0101234567890123450016efe20d0a','78780d0101234567890123450016efe20d0a']

I wouldn't use regex, I would use length; it looks like they are always the same length? — Jon Edwards
– Jon Edwards, Commented Jun 9, 2015 at 14:56

Amit Joki · Accepted Answer · 2015-06-09 15:04:47Z

2

You can split the string with a positive lookahead (?=7878). The regex isn't consuming any characters, so 7878 will be part of the string.

var rgx = /(?=7878)/;
console.log(string1.split(rgx));
console.log(string2.split(rgx));
console.log(string3.split(rgx));

Another option is to split on '7878' and then take all the elements except first and add '7878' to each of them. For example:

var arr = string3.split('7878').slice(1).map(function(str){
    return '7878' + str;
});

That works BUT it also matches strings that do NOT end on 0d0a. How can I only matches those ending on 0d0a OR 0D0A?

Well, then you can use String.match with a plain regex.

console.log(string3.match(/7878.*?0d0a/ig));

edited Jun 9, 2015 at 15:04

answered Jun 9, 2015 at 14:59

Amit Joki

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2 Comments

MagisterMundus Over a year ago

That works BUT it also matches strings that do NOT end on 0d0a. How can I only matches those ending on 0d0a OR 0D0A?

MagisterMundus Over a year ago

Works! Supposing all characters in the string are hex, can I use this regex as well? /7878[a-f0-9]+?0d0a/ig

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