How To Create Sequential File Names In Python

Question

I'm trying to create a script that will create sequential file names for images in a directory with leading zeros. The current code I'm trying to use is:

####Take a picture.
filename='/home/pi/pictures/'print 'img_{0:05d}'.format(i)'.jpg'
self.shoot(filename=filename)

I'm getting a syntax error when running seen here below. http://prnt.sc/dhpf51

The print is outside the quotes and there is no connector to the string before it. And there's no need to put print in there at all. The rest is fine. — elPastor
– elPastor, Commented Dec 10, 2016 at 15:01
Please don't post screenshots (or links to screenshots) of text, paste the actual text into your question; you can use a code block to preserve formatting. See Why may I not upload images of code on SO when asking a question?. — PM 2Ring
– PM 2Ring, Commented Dec 10, 2016 at 15:14

Renjith Thankachan · Accepted Answer · 2016-12-10 15:17:06Z

1

As the screenshot,

filename='/home/pi/pictures/'print 'img_{0:05d}'.format(i)'.jpg'

is not correct syntaxt, you placed the print keyword between format string, you can just use format for creating the path string.

filename='/home/pi/pictures/img_{0:05d}.jpg'.format(i)

answered Dec 10, 2016 at 15:17

Renjith Thankachan

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