Plot multiple histograms with seaborn

Question

I have a data frame with 36 columns. I want to plot histograms for each feature in one go (6x6) using seaborn. Basically reproducing df.hist() but with seaborn. My code below shows the plot for only the first feature and all other come empty.

Test dataframe:

df = pd.DataFrame(np.random.randint(0,100,size=(100, 36)), columns=range(0,36))

My code:

import seaborn as sns
# plot
f, axes = plt.subplots(6, 6, figsize=(20, 20), sharex=True)
for feature in df.columns:
    sns.distplot(df[feature] , color="skyblue", ax=axes[0, 0])

ax=axes[0, 0] means that you plot always to the first axes. This is what you observe as well. Maybe you want to plot to different axes? — ImportanceOfBeingErnest
– ImportanceOfBeingErnest, Commented Nov 6, 2018 at 12:02

ImportanceOfBeingErnest · Accepted Answer · 2018-11-06 12:10:47Z

11

I guess it would make sense to loop over the axes and features simultaneously.

f, axes = plt.subplots(6, 6, figsize=(20, 20), sharex=True)
for ax, feature in zip(axes.flat, df.columns):
    sns.distplot(df[feature] , color="skyblue", ax=ax)

Numpy arrays are flattened by row-wise, i.e. you would get the first 6 features in the first row, the features 6 to 11 in the second row etc.

If this is not what you want, you can define the index for the axes array manually,

f, axes = plt.subplots(6, 6, figsize=(20, 20), sharex=True)
    for i, feature in enumerate(df.columns):
        sns.distplot(df[feature] , color="skyblue", ax=axes[i%6, i//6])

e.g. the above will fill the subplots column by column.

answered Nov 6, 2018 at 12:10

ImportanceOfBeingErnest

342k61 gold badges737 silver badges771 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Plot multiple histograms with seaborn

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related