I have tried extracting text inside quotations ""
file content:
"abc"
"ABC. XYZ"
"1 - 2 - 3"
code i've tried using regex
title = re.findall(r'\"(.+?)\"', filecontent)
print(title)
Output:
['abc']
[] # Some lines comes out like this empty
['1 - 2 - 3']
Some of the lines comes empty not sure why. is there an alternative better way to do this?
If you want to extract some substring out of a string, you can go for re.search.
Demo:
import re
str_list = ['"abc"', '"ABC. XYZ"', '"1 - 2 - 3"']
for str in str_list:
search_str = re.search('"(.+?)"', str)
if search_str:
print(search_str.group(1))
Output:
abc
ABC. XYZ
1 - 2 - 3
IIUC, Do you try this?
filecontent = '''
"abc"
"ABC. XYZ"
"1 - 2 - 3"
'''
re.findall(r'\"(.+?)\"', filecontent)
Output:
['abc', 'ABC. XYZ', '1 - 2 - 3']
My solution is:
import re
my_strings = ['SetVariables "a" "b" "c" ', 'd2efw f "first" +&%#$%"second",vwrfhir, d2e u"third" dwedew', '"uno"?>P>MNUIHUH~!@#$%^&*()_+=0trewq"due" "tre"fef fre f', ' "uno""dos" "tres"', '"unu""doua""trei"', ' "um" "dois" "tres" ']
my_substrings = []
for current_test_string in my_strings:
for values in re.findall(r'\"(.+?)\"', current_test_string):
my_substrings.append(values)
#print("values are:",values,"=")
print(" my_substrings are:",my_substrings,"=")
my_substrings = []
Alternate regular expressions to use are:
The current_test_string.split("\"") approach works if the strings have patterns in which substrings are embedded within quotation marks. This is because it uses the double quotation mark in this example as a delimiter to tokenize the string, and accepts substrings that are not embedded within double quotation marks as valid substring extractions from the string.
References:
