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I'm running raspbian and using this bash script to take a photo every minute and upload it to my FTP server:

#!/bin/bash

while [ 1 ]; do
 DATE=$(date +"%Y-%m-%d_%H_%M_%S")
 raspistill -q 10 -th none -o /home/pi/fb/$DATE.jpg
 curl -T /home/pi/fb/$DATE.jpg  ftp://myftpserver --user myuser:mypass >> /home/pi/fb/log.txt
 sleep 60
 echo finished $DATE >> /home/pi/fb/log.txt
done

I want the output of curl to appear in the log.txt file but it is always printed to the console. Why is that? I also tried to use tee but that didn't change anything.

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2 Answers 2

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curl prints its status to stderr rather than stdout. To capture stderr in the same file, you need to redirect stderr to stdout by adding 2>&1 AFTER your stdout redirection:

curl -T /home/pi/fb/$DATE.jpg  ftp://myftpserver --user myuser:mypass >> /home/pi/fb/log.txt 2>&1

For a thought-provoking question that will help you understand stdout and stderr better... why must the 2>&1 be after the initial >> instead of before?

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0

You are probably seeing output for standard error (stderr) which is a separate stream from standard out (stdout).

It can be redirected with 2>&1 after the output destination.

For Example:

$ curl -T /home/pi/fb/$DATE.jpg ftp://myftpserver --user myuser:mypass >> /home/pi/fb/log.txt 2>&1

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  • Note that while you were on the right track, you've fallen victim to the ol' redirect-stderr-first blunder. Why do you think that doesn't work? Commented Feb 2, 2016 at 16:59

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