How can I know how many directories (in current directory) have at least 1 file with a .mp3 extension.
No need recursion -- directory structure from current dir is for example:
1/blabla.mp3
2
3/something.mp3
4
5
The command should return that there are 2 dirs with mp3 file(s).
find . -type f -name "*.mp3" -exec dirname {} \; | uniq | wc -l
find . ! -name . -prune -type d -exec sh -c '
yes | head -1 |
find "$1/." ! -name . -prune -type f \
\( -name '*.[mM][pP]3' -o -name '.*.[mM][pP]3' \) \
-exec sh -c "read foo" \; -print
' {} {} \; | wc -l |
sh -c 'read n;echo "There are $n dirs with mp3 files."'
The outer "find" selects all the subdirs in the current dir. and then descends in each of these and finds non-recursively in them if they contain atleast 1 mp3 file including hidden and in a case insensitive manner.
